frogriverone javascript

Download ZIP FrogRiverOne JavaScript solution 100%/100% Raw frogriverone.js function solution(X, A) { if (A.length === 1) { // If the array is one element // And if its first item is 1 as well as the value to search for, // the frog doesn't need to move if (A[0] === 1 && X === 1) return 0; // If not, it's impossible to go anywhere else return -1; } The problem is to find the earliest time when a frog can jump to the other side of a river. You are given a non-empty zero-indexed array A consisting of N integers representing the falling leaves. rev2022.11.14.43031. To learn more, see our tips on writing great answers. 60. I know my solution is incorrect, but I hope it can help (it's on JS): I don't need a solution to the task, I just need its clearer explanation, i.e what I have to do to solve it. Please don't post code-only answers but add a little textual explanation about how and why your approach works and why it's different from the other answers given. Anyway, here's my solution: Here's a maximum score solution in C++ for completeness: I was searching for the optimum in performance and space but also elegance. D. A small frog wants to get to the other side of a river. You may assume that the speed of the current in the river is negligibly small, i.e. Hanging in a vue component with async / await call, vs for describing ordinary people. Leaves fall from a tree onto the surface of the river.You are given an array A consisting of N integers representing the falling leaves. The frog can cross only when leaves appear at every position across the river from 1 to X. Cannot retrieve contributors at this time. the leaves do not change their positions once they fall in the river.For example, you are given integer X = 5 and array A such that: A[0] = 1 A[1] = 3 A[2] = 1 A[3] = 4 A[4] = 2 A[5] = 3 A[6] = 5 A[7] = 4In second 6, a leaf falls into position 5. So quick too! You are given an array A consisting of N integers representing the falling leaves. Lesson 4 -Counting Elements.Task Description:A small frog wants to get to the other side of a river. This is the earliest time when leaves appear in every position across the river.Write a function:class Solution { public int solution(int X, int[] A); }that, given a non-empty array A consisting of N integers and integer X, returns the earliest time when the frog can jump to the other side of the river.If the frog is never able to jump to the other side of the river, the function should return 1.For example, given X = 5 and array A such that: A[0] = 1 A[1] = 3 A[2] = 1 A[3] = 4 A[4] = 2 A[5] = 3 A[6] = 5 A[7] = 4the function should return 6, as explained above.Write an efficient algorithm for the following assumptions:N and X are integers within the range [1..100,000];each element of array A is an integer within the range [1..X]. 63 lines (60 sloc) 2.27 KB. 7. // And if its first item is 1 as well as the value to search for, // If not, it's impossible to go anywhere, // If we've already found the element, continue, // If we haven't found the element, mark it, // Add to the comparison sum that we will be using, // to determine whether the frog will have been, // able to cross successfully by this point and then, // If the counter is over the length, we didn't find it. The frog is currently located at position 0, and wants to get to position X. Leaves fall from a tree onto the surface of the river. The main strategy is to use java.util.Set to store all required integers for a full jump and a second java.util.Set to keep storing current leaves and to keep checking if the first set fully exists in the second set. Way to create these kind of "gravitional waves". Cannot retrieve contributors at this time. FrogRiverOne.js function solution(X, A) { // write your code in JavaScript (Node.js 6.4.0) let sequence = [0]; let position = -1; let counter = 0; if (X === 1 && A[0] === 1) return 0; for (let i = 0; i <= A.length - 1; i++) { if (A[i] <= X) { if (!sequence[A[i]]) { counter++; } sequence[A[i]] = A[i]; if (counter === X) { position = i; break; } } } It not only uses bitwise to come with an "equation" to solve that specific problem, which is always an interesting approach, but with that it is possible to have auxiliary space of O(1). What is the purpose of the arrow on the flightdeck of USS Franklin Delano Roosevelt? What are the arguments *against* Jesus calming the storm meaning Jesus = God Almighty? Your variable names are completely unhelpful. Solution Class solution Method. You are given a non-empty zero-indexed array A consisting of N integers representing the falling leaves. Here's what I had in mind: Thanks for your answer! A[K] represents the position where one leaf falls at time K, measured in seconds.The goal is to find the earliest time when the frog can jump to the other side of the river. Making statements based on opinion; back them up with references or personal experience. Leaves fall from a tree onto the surface of the river. What is the difference between these 2 ways of creating a list of arrays in JavaScript? What am I missing? The frog is initially located on one bank of the river (position 0) and wants to get to the opposite bank (position X+1). The frog is initially located on one bank of the river (position 0) and wants to get to the opposite bank (position X+1). "I've googled and asked people about this question" what question? Moving variables around and out of functions. Lesson 4 -Counting Elements.Task Description:A small frog wants to get to the other side of a river. Why the difference between double and electric bass fingering? Code definitions. Learn more about bidirectional Unicode characters. Elements of input arrays can be modified. About The Author Dan Avramescu Complexity: expected worst-case time complexity is O(N); Function to find the shortest word in an array, where not every element is a string. This is the earliest time when leaves appear in every position across the river. Why does this recursive javascript function expression return undefined? CTRL + SPACE for auto-complete. Leaves fall from a tree onto the surface of the river. How can I see the httpd log for outbound connections? Since all position changes are steps of size 1 a regular position counter is sufficient. each element of array A is an integer within the range [1..X]. // If we reached this point and this conditional is true. 7 Min read. Your solution is actually almost correct, but you overcomplicated the evaluation. The frog is initially located on one bank of the river (position 0) and wants to get to the opposite bank (position X+1). Link FrogRiverOne Complexity: expected worst-case time complexity is O (N); expected worst-case space complexity is O (X) Execution: Mark seen elements as such in a boolean array. The frog can cross only when leaves appear at every position across the river from 1 to X (that is, we want to find the earliest moment when all the positions from 1 to X are covered by leaves). * A small frog wants to get to the other side of a river. Being a Set can only contain unique values, you can simply iterate through array A, adding the values into a Set until the size of Set equals the integer X, at which point that array key is the solution. Would you maybe provide some explanation to your answer so that others can understand it better? The goal is to find the earliest time when the frog can jump to the other side of the river. Instantly share code, notes, and snippets. Okay, I figured out your problem for you. How to Create a Set You can create a JavaScript Set by: Passing an Array to new Set () Create a new Set and use add () to add values Create a new Set and use add () to add variables The new Set () Method Pass an Array to the new Set () constructor: Example // Create a Set const letters = new Set ( ["a","b","c"]); Try it Yourself Thanks for contributing an answer to Stack Overflow! Thanks for sharing. 3. For example, you are given integer X = 5 and array A such that: A [0] = 1 A [1] = 3 A [2] = 1 A [3] = 4 You may assume that the speed of the current in the river is negligibly small, i.e. Just a few improvements. If the frog is never able to jump to the other side of the river, the function should return 1. Codility / FrogRiverOne.java / Jump to. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. i dont understand the problem, but here is the description: Mt Safranka, I've added a counter and modified the first loop this way: let c = 0; for(i=0; i

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